If $\frac{x^3}{(2x - 1)(x + 2)(x - 3)} = p + \frac{q}{2x - 1} + \frac{r}{x + 2} + \frac{s}{x - 3}$,then:
- A$p = 1$
- B$p = 2$
- C$p = \frac{1}{2}$
- D$6q - 3r + 2s = 3$
Explore More
Similar Questions
If $\frac{1}{x^4+1}=\frac{A x+B}{x^2+\sqrt{2} x+1}+\frac{C x+D}{x^2-\sqrt{2} x+1}$ then $B D-A C=$
If $\frac{x^4}{(x-1)(x-2)(x-3)} = x+k+\frac{A}{x-1}+\frac{B}{x-2}+\frac{C}{x-3}$,then $k+A-B+C=$
If $\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}$, then $2 A+3 B-C-D+E=$
DifficultTS EAMCET 2024
View SolutionWhat is the coefficient of $x^4$ in the expansion of $\frac{3x}{(x - 2)(x + 1)}$?
Difficult
View SolutionIf $\frac{(x - 1)^2}{x^3 + x} = \frac{A}{x} + \frac{Bx + C}{x^2 + 1}$,then
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo