If sin(xy) + cos(xy) = 0,then frac{dy}{dx} = | vedclass

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(B) Given equation: $\sin(xy) + \cos(xy) = 0$This implies $\sin(xy) = -\cos(xy)$,which means $	an(xy) = -1$.Since $	an(xy) = -1$,we have $xy = n\pi

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$-\frac{y}{x}$

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(B) Given equation: $\sin(xy) + \cos(xy) = 0$This implies $\sin(xy) = -\cos(xy)$,which means $	an(xy) = -1$.Since $	an(xy) = -1$,we have $xy = n\pi - \frac{\pi}{4}$ for some integer $n$.Differentiating both sides with respect to $x$:$\frac{d}{dx}(xy) = \frac{d}{dx}(n\pi - \frac{\pi}{4})$$y + x \frac{dy}{dx} = 0$$x \frac{dy}{dx} = -y$$\frac{dy}{dx} = -\frac{y}{x}$

If $\sin(xy) + \cos(xy) = 0$,then $\frac{dy}{dx} = $

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