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(D) In a body-centered cubic $(bcc)$ unit cell,the body-centered atom is located at the center of the cube. The distance from the center of the cube t

Vedclass · Accepted Answer

$\frac{\sqrt{3}}{2} a$

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(D) In a body-centered cubic $(bcc)$ unit cell,the body-centered atom is located at the center of the cube. The distance from the center of the cube to any corner is equal to half of the body diagonal. The length of the body diagonal of a cube with side length $a$ is $\sqrt{3} a$. Therefore,the distance between the body-centered atom and one corner atom is $\frac{1}{2} 	imes \sqrt{3} a = \frac{\sqrt{3}}{2} a$.

If $a$ is the length of the side of a cube,the distance between the body-centered atom and one corner atom in the cube will be

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