If $(1 + x - 3x^2)^{2145} = a_0 + a_1x + a_2x^2 + \dots$,then $a_0 - a_1 + a_2 - a_3 + \dots$ ends with:

  • A
    $1$
  • B
    $3$
  • C
    $7$
  • D
    $9$

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