If $S_n = \sum_{r=0}^n \frac{1}{^nC_r}$ and $T_n = \sum_{r=0}^n \frac{r}{^nC_r}$,then $\frac{T_n}{S_n}$ is equal to

  • A
    $\frac{n}{2}$
  • B
    $\frac{n}{2} - 1$
  • C
    $n - 1$
  • D
    $\frac{2n - 1}{2}$

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