If Pb^{2+}, Cu^{2+}, Al^{3+}, Cd^{2+}, Zn^{2+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. When $H^{+}/H_2S$ is added,$Pb^{2+}$,$Cu^{2+}$,and $Cd^{2+}$ precipitate as their respective sulfides ($PbS$,$CuS$,$CdS$) because they belong

Vedclass · Accepted Answer

Clear solution in which two radicals are present as a soluble complex

Vedclass · Answer

(B) $1$. When $H^{+}/H_2S$ is added,$Pb^{2+}$,$Cu^{2+}$,and $Cd^{2+}$ precipitate as their respective sulfides ($PbS$,$CuS$,$CdS$) because they belong to Group $II$ of the qualitative analysis scheme.$2$. The remaining ions in solution $(X)$ are $Al^{3+}$ and $Zn^{2+}$.$3$. When excess $NaOH$ is added to solution $(X)$ containing $Al^{3+}$ and $Zn^{2+}$,both form soluble complexes.$4$. $Al^{3+} + 4OH^{-} \rightarrow [Al(OH)_4]^{-}$ (soluble aluminate).$5$. $Zn^{2+} + 4OH^{-} \rightarrow [Zn(OH)_4]^{2-}$ (soluble zincate).$6$. Thus,a clear solution is obtained containing two radicals as soluble complexes.

If $Pb^{2+}, Cu^{2+}, Al^{3+}, Cd^{2+}, Zn^{2+}$ radicals are present in an aqueous solution,and it reacts with $H^{+}/H_2S$,a precipitate is produced. The solution $(X)$ obtained after the removal of the precipitate is treated with excess $NaOH$. What is the result?

Similar Questions

$A$ white crystalline substance dissolves in water. On passing $H_2S$ in this solution,a black precipitate is obtained. The black precipitate dissolves completely in hot $HNO_3$. On adding a few drops of conc. $H_2SO_4$ a white precipitate is obtained. This precipitate is that of:

Which of the following sulphates is insoluble in water?

$A$ solution contains $Cl^{-}$,$I^{-}$,and $SO_{4}^{2-}$ ions. Which of the following ions is capable of precipitating all of the above when added to this solution?

In which of the following is $NH_{3}$ not used?

Which of the following compounds can produce Rinmann's green with $Co(NO_3)_2$ solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module