If $S_1, S_2, S_3$ and $S_4$ are the solubilities of $AgCl$ in water,in $0.01 \ M \ CaCl_2$,in $0.01 \ M \ NaCl$ and in $0.05 \ M \ AgNO_3$ respectively at a certain temperature,the correct order of solubilities is

  • A
    $S_1 > S_2 > S_3 > S_4$
  • B
    $S_1 > S_3 > S_2 > S_4$
  • C
    $S_1 > S_2 = S_3 > S_4$
  • D
    $S_1 > S_3 > S_4 > S_2$

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