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(B) The symmetric difference of two sets $A$ and $B$ is defined as $A \Delta B = (A - B) \cup (B - A)$.Since $A$ is a proper subset of $B$ ($A \subset

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$1$

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(B) The symmetric difference of two sets $A$ and $B$ is defined as $A \Delta B = (A - B) \cup (B - A)$.Since $A$ is a proper subset of $B$ ($A \subset B$ and $A 
eq B$),we have $A - B = \emptyset$,so $n(A - B) = 0$.Because $A$ is a proper subset of $B$,there must be at least one element in $B$ that is not in $A$,which means $n(B - A) \geq 1$.Therefore,$n(A \Delta B) = n(A - B) + n(B - A) = 0 + n(B - A) \geq 1$.The minimum possible value of $n(A \Delta B)$ is $1$.

If $A$ and $B$ are any two non-empty sets and $A$ is a proper subset of $B$. If $n(A) = 4$,then the minimum possible value of $n(A \Delta B)$ is (where $\Delta$ denotes the symmetric difference of set $A$ and set $B$).

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