(B) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2} CV^2$.Given:Capacitance $C = 12 \ pF = 12 \times 10^{-12} \ F$Potent

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(B) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2} CV^2$.Given:Capacitance $C = 12 \ pF = 12 \times 10^{-12} \ F$Potential difference $V = 50 \ V$Substituting the values into the formula:$U = \frac{1}{2} \times (12 \times 10^{-12} \ F) \times (50 \ V)^2$$U = 6 \times 10^{-12} \times 2500 \ J$$U = 15000 \times 10^{-12} \ J$$U = 1.5 \times 10^4 \times 10^{-12} \ J$$U = 1.5 \times 10^{-8} \ J$Therefore,the correct option is $B$.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

Easy

If a $12 \ pF$ capacitor is connected to a $50 \ V$ battery,then the electrostatic energy stored in the capacitor is . . . . . . .

GSEB 2024 All GSEB

A
$1.5 \times 10^{-12} \ J$
B
$1.5 \times 10^{-8} \ J$
C
$1.5 \times 10^{-6} \ J$
D
$3 \times 10^{-8} \ J$

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Electric Potential and Capacitance

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Energy Stored in a Capacitor

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If a $12 \ pF$ capacitor is connected to a $50 \ V$ battery,then the electrostatic energy stored in the capacitor is . . . . . . .

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