If A borrowed ₹P at x% and B borrowed ₹Q (Q | vedclass

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(A) Let the time after which the amounts are equal be $N$ years.Amount of debt for $A = P + 	ext{Simple Interest} = P + \frac{P 	imes x 	imes N}{10

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$100\left(\frac{Q-P}{Px-Qy}\right)$ years

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(A) Let the time after which the amounts are equal be $N$ years.Amount of debt for $A = P + 	ext{Simple Interest} = P + \frac{P 	imes x 	imes N}{100}$.Amount of debt for $B = Q + 	ext{Simple Interest} = Q + \frac{Q 	imes y 	imes N}{100}$.Since the amounts are equal,we set them equal to each other:$P + \frac{PxN}{100} = Q + \frac{QyN}{100}$.Rearranging the terms to solve for $N$:$\frac{PxN}{100} - \frac{QyN}{100} = Q - P$.$N \left(\frac{Px - Qy}{100}ight) = Q - P$.$N = 100 \left(\frac{Q - P}{Px - Qy}ight)$ years.

If $A$ borrowed $₹P$ at $x\%$ and $B$ borrowed $₹Q$ $(Q > P)$ at $y\%$ per annum at simple interest at the same time,then the amount of their debts will be equal after:

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