If a capacitor of capacity $900 \mu F$ is charged to $100 \ V$ and its total energy is transferred to a capacitor of capacity $100 \mu F$, then its potential will be (in $V$)

If the charge on a body is increased by $2 \ C$,the energy stored in it increases by $21 \%$. The original charge on the body in coulomb is:

$A$ parallel plate capacitor has plate area $A$ and separation between plates is $d$. It is charged to a potential difference of $V_0$ volt. The charging battery is then disconnected and plates are pulled apart to three times the initial distance. The work done to increase the distance between the plates is $(\varepsilon_0 = \text{permittivity of free space})$

An air-filled parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A$,the energy stored in the capacitor is ($\epsilon_{0} =$ permittivity of free space).

Write three different formulas for the energy stored in a capacitor.

$A$ parallel plate air capacitor has a uniform electric field $E$ in the space between the plates. The area of each plate is $A$ and the distance between the plates is $d$. The energy stored in the capacitor is $[\varepsilon_0 = \text{permittivity of free space}]$