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Question

(B) For a charged spherical conductor of radius $R = 10 \,cm$, the potential inside the conductor (at any distance $r < R$) is constant and equal to t

Vedclass · Accepted Answer

$2V/3$

Vedclass · Answer

(B) For a charged spherical conductor of radius $R = 10 \,cm$, the potential inside the conductor (at any distance $r Given that the potential at $r = 5 \,cm$ is $V$, the potential at the surface $(r = 10 \,cm)$ is also $V$.The potential at a distance $r$ from the centre for $r > R$ is given by $V(r) = \frac{kQ}{r}$, where $kQ$ is the potential at the surface times the radius $(V 	imes R)$.Thus, $V(r) = \frac{V 	imes R}{r}$.Substituting the values $R = 10 \,cm$ and $r = 15 \,cm$:$V(15) = \frac{V 	imes 10}{15} = \frac{2}{3} V$.

If a charged spherical conductor of radius $10 \,cm$ has potential $V$ at a point distant $5 \,cm$ from its centre, then the potential at a point distant $15 \,cm$ from the centre will be

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