If a colour blind woman marries a normal visioned man,their sons will be

  • A
    all colour blind
  • B
    all normal visioned
  • C
    one-half colour blind and one-half normal
  • D
    three-fourths colour blind and one-fourth normal

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$A$: The heterozygotic female for haemophilia may transmit the disease to sons.
$R$: Such traits show criss-cross inheritance.

Both sickle cell anaemia and Huntington's chorea are

Given below is a pedigree chart showing the inheritance of a certain sex-linked trait in humans. The trait traced in the above pedigree chart is

Match Column-$I$ with Column-$II$ and select the correct option.
Column-$I$ Column-$II$
$(P)$ Haemophilia $(i)$ Recessive gene: $X^{h}X^{h}$
$(Q)$ Colour blindness $(ii)$ Recessive gene: $pp$
$(R)$ Phenylketonuria $(iii)$ Recessive gene: $Hb^{s}Hb^{s}$
$(S)$ Sickle-cell anaemia $(iv)$ Recessive gene: $X^{c}X^{c}$

Color blindness is more common in males because it is a:

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