If a current of 15 ,A passes through a soleno | vedclass

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Question

(C) The magnetic moment $M$ of a solenoid is given by the formula $M = N \cdot I \cdot A$,where $N$ is the number of turns,$I$ is the current,and $A$

Vedclass · Accepted Answer

$3 \pi \,J \,T^{-1}$

Vedclass · Answer

(C) The magnetic moment $M$ of a solenoid is given by the formula $M = N \cdot I \cdot A$,where $N$ is the number of turns,$I$ is the current,and $A$ is the cross-sectional area of the solenoid.Given:Number of turns $N = 500$Current $I = 15 \,A$Radius $r = 2 \,cm = 0.02 \,m$Area $A = \pi r^2 = \pi (0.02)^2 = 0.0004 \pi \,m^2$Substituting these values into the formula:$M = 500 	imes 15 	imes 0.0004 \pi$$M = 7500 	imes 0.0004 \pi$$M = 3 \pi \,J \,T^{-1}$Therefore,the correct option is $C$.

If a current of $15 \,A$ passes through a solenoid of length $25 \,cm$,radius $2 \,cm$ and number of turns $500$,then the magnetic moment of the solenoid is

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