If a dielectric slab is inserted in the capac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The brightness of the bulb depends on the power dissipated in the circuit,which is given by $P = I_{rms}^2 R_{bulb}$.$2$. The current in the

Vedclass · Accepted Answer

Increase

Vedclass · Answer

(A) $1$. The brightness of the bulb depends on the power dissipated in the circuit,which is given by $P = I_{rms}^2 R_{bulb}$.$2$. The current in the $RC$ circuit is given by $I_{rms} = \frac{V_{rms}}{Z}$,where $Z = \sqrt{R_{total}^2 + X_C^2}$ is the impedance of the circuit.$3$. Here,$X_C = \frac{1}{\omega C}$ is the capacitive reactance.$4$. When a dielectric slab is inserted into the capacitor,the capacitance $C$ increases ($C' = KC$,where $K > 1$).$5$. As $C$ increases,the capacitive reactance $X_C = \frac{1}{\omega C}$ decreases.$6$. Since $Z = \sqrt{R_{total}^2 + X_C^2}$,a decrease in $X_C$ leads to a decrease in the total impedance $Z$.$7$. $A$ decrease in impedance $Z$ results in an increase in the current $I_{rms}$ flowing through the circuit.$8$. Since $P = I_{rms}^2 R_{bulb}$,an increase in $I_{rms}$ leads to an increase in the power dissipated by the bulb,hence the brightness of the bulb will increase.

If a dielectric slab is inserted in the capacitor of the given $RC$ circuit,then the brightness of the bulb will:

Similar Questions

An electric lamp connected in series with a capacitor and an a.c. source is glowing with certain brightness. On reducing the frequency of the source, the brightness of the lamp

An e.m.f. $E=4 \cos (1000 t)$ volt is applied to an $LR$ circuit of inductance $3 \ mH$ and resistance $4 \ \Omega$. The maximum current in the circuit is

In the $AC$ circuit shown,$E = E_0 \sin(\omega t + \phi)$ and $i = i_0 \sin(\omega t + \phi + \frac{\pi}{4})$. Then,the box contains:

In an $LCR$ series $a.c.$ circuit,the voltage across each of the components $L, C$ and $R$ is $60 \,V$. The voltage across the $LC$ combination is

Switch $S$ is closed at $t = 0$. After a sufficiently long time,an iron rod is inserted into the inductor $L$. Then,the light bulb:

Vedclass Test Series

Exam Paper Generator

Online Exam Module