If a double stranded DNA has 20 percent of cy | vedclass

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(B) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of purines is equal to the amount of pyrimidines.Specifically,the amou

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$30$

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(B) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of purines is equal to the amount of pyrimidines.Specifically,the amount of adenine $(A)$ equals the amount of thymine $(T)$,and the amount of guanine $(G)$ equals the amount of cytosine $(C)$.Given that cytosine $(C)$ is $20 \%$,then guanine $(G)$ must also be $20 \%$.Therefore,the total percentage of $G + C$ is $20 \% + 20 \% = 40 \%$.The remaining percentage for $A + T$ is $100 \% - 40 \% = 60 \%$.Since $A = T$,the percentage of adenine $(A)$ is $60 \% / 2 = 30 \%$.

If a double stranded $DNA$ has $20$ percent of cytosine,calculate the percent of adenine in the $DNA$. (in $\%$)

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