If a line segment joining the mid-points of two chords of a circle passes through the centre of the circle,prove that the two chords are parallel.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Given: $AB$ and $CD$ are two chords of a circle with centre $O$. The mid-points of $AB$ and $CD$ are $L$ and $M$ respectively.
To prove: $AB \parallel CD$
Proof: Since $L$ is the mid-point of chord $AB$,therefore $OL \perp AB$,or $\angle ALO = 90^{\circ}$.
[Because the line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]
Similarly,$\angle CMO = 90^{\circ}$.
Therefore,$\angle ALO = \angle CMO = 90^{\circ}$.
Since these are corresponding angles formed by the transversal $LM$ intersecting lines $AB$ and $CD$,and they are equal,the lines must be parallel.
So,$AB \parallel CD$.
Hence,proved.

Explore More

Similar Questions

$A$ circle has a radius of $\sqrt{2} \text{ cm}$. It is divided into two segments by a chord of length $2 \text{ cm}$. Prove that the angle subtended by the chord at a point in the major segment is $45^{\circ}$.

Difficult
View Solution

In the figure,$BC$ is a diameter of the circle and $\angle BAO = 60^{\circ}$. Then $\angle ADC$ is equal to: (in $^{\circ}$)

In the figure,if $\angle OAB = 40^{\circ},$ then $\angle ACB$ is equal to: (in $^{\circ}$)

The circumcentre of the triangle $ABC$ is $O$. Prove that $\angle OBC + \angle BAC = 90^{\circ}$.

Difficult
View Solution

In a cyclic quadrilateral $PQRS$,$\angle P = \angle R + 50^{\circ}$. Find $\angle P$ and $\angle R$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo