If a man walks at the rate of 5, km/h,he miss | vedclass

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(B) Let the distance to the station be $D\, km$ and the scheduled time of the train be $T\, hours$.Case $1$: When walking at $5\, km/h$,he is late by

Vedclass · Accepted Answer

$6$

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(B) Let the distance to the station be $D\, km$ and the scheduled time of the train be $T\, hours$.Case $1$: When walking at $5\, km/h$,he is late by $7\, minutes$ $(7/60\, hours)$.Time taken = $D/5 = T + 7/60$.Case $2$: When walking at $6\, km/h$,he reaches $5\, minutes$ $(5/60\, hours)$ early.Time taken = $D/6 = T - 5/60$.Subtracting the second equation from the first:$(D/5) - (D/6) = (T + 7/60) - (T - 5/60)$.$(6D - 5D) / 30 = 12/60$.$D/30 = 1/5$.$D = 30/5 = 6\, km$.Therefore,the distance to the station is $6\, km$.

If a man walks at the rate of $5\, km/h$,he misses a train by $7\, minutes$. However,if he walks at the rate of $6\, km/h$,he reaches the station $5\, minutes$ before the arrival of the train. The distance covered by him to reach the station is (in $km$)

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