If a source of electromagnetic radiation havi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power $P$ of the source is $15 	ext{ kW} = 15 	imes 10^3 	ext{ W}$.The number of photons produced per second $n = 10^{16} 	ext{ s}^{-1}$.T

Vedclass · Accepted Answer

Gamma rays

Vedclass · Answer

(C) The power $P$ of the source is $15 	ext{ kW} = 15 	imes 10^3 	ext{ W}$.The number of photons produced per second $n = 10^{16} 	ext{ s}^{-1}$.The energy of one photon $E$ is given by $E = \frac{P}{n} = \frac{15 	imes 10^3}{10^{16}} = 15 	imes 10^{-13} 	ext{ J}$.Using the relation $E = h
u$,we find the frequency $
u$:$
u = \frac{E}{h} = \frac{15 	imes 10^{-13}}{6 	imes 10^{-34}} = 2.5 	imes 10^{21} 	ext{ Hz}$.Electromagnetic radiation with a frequency of $2.5 	imes 10^{21} 	ext{ Hz}$ falls in the range of Gamma rays (which typically have frequencies greater than $10^{19} 	ext{ Hz}$).

If a source of electromagnetic radiation having power $15 \text{ kW}$ produces $10^{16}$ photons per second,the radiation belongs to which part of the spectrum? (Take Planck constant $h = 6 \times 10^{-34} \text{ Js}$)

Similar Questions

The number of wavelengths in the visible spectrum is:

The ozone layer in the Earth's atmosphere is essential for the protection of human life because it...

. . . . . . are used in medicine to destroy cancer cells.

The ozone layer absorbs

What is the use or importance of the ozone layer?

Vedclass Test Series

Exam Paper Generator

Online Exam Module