If a thin prism of glass is dipped into water,then the minimum deviation (with respect to air) of light produced by the prism will be: $\left( {_a{\mu _g} = \frac{3}{2} \text{ and } _a{\mu _w} = \frac{4}{3}} \right)$

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • C
    $2$
  • D
    $\frac{1}{5}$

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