If action is always equal to the reaction,explain how a horse can pull a cart.
- AThe horse pulls the cart with a force greater than the reaction force.
- BThe horse pushes the ground backward,and the reaction force from the ground moves the horse forward.
- CThe cart moves because the horse is stronger than the cart.
- DThe friction between the cart and the ground is zero.
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$A$ motorcar of mass $1200\, kg$ is moving along a straight line with a uniform velocity of $90\, km/h$. Its velocity is slowed down to $18\, km/h$ in $4\, s$ by an unbalanced external force. Calculate the acceleration and change in momentum. Also,calculate the magnitude of the force required.
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View SolutionWhat is the momentum of an object of mass $m$, moving with a velocity $v$?
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View Solution$A$ truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of $400 \, m$ in $20 \, s$. Find the force (in $N$) acting on it if its mass is $7 \, \text{tonnes}$ $(1 \, \text{tonne} = 1000 \, kg)$.
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View SolutionThe following is the distance-time table of an object in motion:
Time in seconds Distance in metres $0$ $0$ $1$ $1$ $2$ $8$ $3$ $27$ $4$ $64$ $5$ $125$ $6$ $216$ $7$ $343$
$(a)$ What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero?
$(b)$ What do you infer about the forces acting on the object?
| Time in seconds | Distance in metres |
| $0$ | $0$ |
| $1$ | $1$ |
| $2$ | $8$ |
| $3$ | $27$ |
| $4$ | $64$ |
| $5$ | $125$ |
| $6$ | $216$ |
| $7$ | $343$ |
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$(b)$ What do you infer about the forces acting on the object?
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View SolutionAn object experiences a net zero external unbalanced force. Is it possible for the object to be travelling with a non-zero velocity? If yes,state the conditions that must be placed on the magnitude and direction of the velocity. If no,provide a reason.
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