(B) The letters of the word $MASK$ in alphabetical order are $A, K, M, S$. Total number of permutations is $4! = 24$. Words starting with $A$: $3! = 6

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(B) The letters of the word $MASK$ in alphabetical order are $A, K, M, S$. Total number of permutations is $4! = 24$. Words starting with $A$: $3! = 6$ words ($1$ to $6$). Words starting with $K$: $3! = 6$ words ($7$ to $12$). Words starting with $M$: $3! = 6$ words ($13$ to $18$). Words starting with $S$: $SAKM$ ($19^{th}$ word),$SA MK$ ($20^{th}$ word),$SKAM$ ($21^{st}$ word),$SKMA$ ($22^{nd}$ word),$SMAK$ ($23^{rd}$ word),$SMKA$ ($24^{th}$ word). Thus,the $19^{th}$ word is $SAKM$.

Class 11 Mathematics Permutation and Combination Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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If all permutations of the letters of the word $MASK$ are arranged in the order as in a dictionary,with or without meaning,which one of the following is the $19^{th}$ word?

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A
$KAMS$
B
$SAKM$
C
$AKMS$
D
$AMSK$

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Permutation and Combination

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Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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If all permutations of the letters of the word $MASK$ are arranged in the order as in a dictionary,with or without meaning,which one of the following is the $19^{th}$ word?

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