If the average depth of an ocean is 4000 m a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The bulk modulus $B$ is defined as $B = -\frac{\Delta P}{\Delta V / V}$.The pressure at the bottom of the ocean is given by the hydrostatic pressu

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The bulk modulus $B$ is defined as $B = -\frac{\Delta P}{\Delta V / V}$.The pressure at the bottom of the ocean is given by the hydrostatic pressure formula: $\Delta P = ho g h$.Substituting the given values: $\Delta P = 1000 \ kg m^{-3} 	imes 10 \ m s^{-2} 	imes 4000 \ m = 4 	imes 10^7 \ N m^{-2}$.The fractional compression is $\frac{\Delta V}{V} = \frac{\Delta P}{B}$.Substituting the values: $\frac{\Delta V}{V} = \frac{4 	imes 10^7}{2 	imes 10^9} = 2 	imes 10^{-2}$.Comparing this with $\alpha 	imes 10^{-2}$,we get $\alpha = 2$.

Similar Questions

When the temperature of a gas is $20^{\circ} C$ and pressure is changed from $P_1 = 1.01 \times 10^5 \, Pa$ to $P_2 = 1.165 \times 10^5 \, Pa$,the volume changes by $10 \%$. The Bulk modulus is ......... $\times 10^5 \, Pa$.

The Bulk Modulus for an incompressible liquid is

When a pressure of $100 \, atm$ is applied to a rubber ball,its volume decreases by $0.01 \%$. What is the bulk modulus of the rubber?

The adiabatic elasticity of a gas is equal to

The compressibility of water is $5 \times 10^{-10} \ m^2/N$. $A$ pressure of $15 \times 10^6 \ Pa$ is applied on $100 \ ml$ volume of water. The change in the volume of water is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module