If 1,3-butadiene is polymerized by a free rad | vedclass

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(A) The polymerization of $1,3$-butadiene $(CH_2=CH-CH=CH_2)$ via free radical mechanism involves $1,4$-addition.This results in the formation of poly

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$(i) \& (ii)$

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(A) The polymerization of $1,3$-butadiene $(CH_2=CH-CH=CH_2)$ via free radical mechanism involves $1,4$-addition.This results in the formation of polybutadiene,which can exist in two geometric isomeric forms due to the double bond in the polymer chain:$1$. $cis$-$1,4$-polybutadiene (represented by structure $(i)$).$2$. $trans$-$1,4$-polybutadiene (represented by structure $(ii)$).Structure $(iii)$ represents a saturated chain which is not formed by the $1,4$-polymerization of $1,3$-butadiene.Therefore,the possible products contain repeating units $(i)$ and $(ii)$.

If $1,3$-butadiene is polymerized by a free radical synthesis,the possible product contains which repeating units?

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