If compound MX_4 has mu = 0,then the most pro | vedclass

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(B) For a compound $MX_4$ to have a dipole moment $\mu = 0$,the molecule must be highly symmetric such that the individual bond dipoles cancel each ot

Vedclass · Accepted Answer

Square planar

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(B) For a compound $MX_4$ to have a dipole moment $\mu = 0$,the molecule must be highly symmetric such that the individual bond dipoles cancel each other out.In a square planar geometry,the four $X$ atoms are arranged at the corners of a square around the central atom $M$,with bond angles of $90^{\circ}$. The dipole moments of opposite bonds cancel each other,resulting in a net dipole moment of $\mu = 0$.While a regular tetrahedral geometry also has $\mu = 0$,it is not listed as an option. Among the given choices,square planar is the correct geometry that allows for a net dipole moment of zero.

If compound $MX_4$ has $\mu = 0$,then the most probable geometry will be:

Similar Questions

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