If the distance between two $Pt$ electrodes is $2 \, cm$,the cross-sectional area is $4.0 \, cm^2$,and the resistance is $25 \, \Omega$,find the molar conductivity of a $0.5 \, M$ solution.

  • A
    $40 \, S \, cm^2 \, mol^{-1}$
  • B
    $20 \, S \, cm^2 \, mol^{-1}$
  • C
    $80 \, S \, cm^2 \, mol^{-1}$
  • D
    $10 \, S \, cm^2 \, mol^{-1}$

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Explain the difficulties encountered in the measurement of the resistance of ionic solutions and how to resolve them.

The molar conductivity of $KCl$ solutions at different concentrations at $298 \, K$ are given below:
$c^{1/2} / (mol \, L^{-1})^{1/2}$$\Lambda_m / S \, cm^2 \, mol^{-1}$
$0.000198$$148.61$
$0.000309$$148.29$
$0.000521$$147.81$
$0.000989$$147.09$

Show that a plot between $\Lambda_m$ and $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.

$A$ $5.0 \, mmol \, dm^{-3}$ aqueous solution of $KCl$ has a conductance of $0.55 \, mS$ when measured in a cell with a cell constant of $1.3 \, cm^{-1}$. The molar conductivity of this solution is ....... $mS \, m^{2} \, mol^{-1}$. (Round off to the Nearest Integer)

Which of the following has maximum conductivity in solution?

The conductivity of a centimolar solution of $KCl$ at $298\text{ K}$ is $0.021\text{ }\Omega^{-1}\text{ cm}^{-1}$ and the resistance of the cell containing the solution at $298\text{ K}$ is $60\text{ }\Omega$. The value of the cell constant $(G^*)$ is (in $text{ cm}^{-1}$)

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