If five equal pieces of wire having 5, Omega | vedclass

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Question

(A) When a wire of resistance $R$ is cut into $n$ equal pieces,the resistance of each piece becomes $R' = R/n$.Here,the original resistance $R = 5\, \

Vedclass · Accepted Answer

$0.2\, \Omega$

Vedclass · Answer

(A) When a wire of resistance $R$ is cut into $n$ equal pieces,the resistance of each piece becomes $R' = R/n$.Here,the original resistance $R = 5\, \Omega$ and the number of pieces $n = 5$.Therefore,the resistance of each piece $R' = 5\, \Omega / 5 = 1\, \Omega$.When $n$ resistors of equal resistance $R'$ are connected in parallel,the equivalent resistance $R_{eq}$ is given by $R_{eq} = R'/n$.Substituting the values,$R_{eq} = 1\, \Omega / 5 = 0.2\, \Omega$.

If five equal pieces of wire having $5\, \Omega$ resistance are made and connected in parallel,then their equivalent resistance will be $......$

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