If for a sucrose solution the elevation in bo | vedclass

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(B) Elevation in boiling point $(\Delta T_b)$ is a colligative property,which depends on the number of particles in the solution.The formula is $\Delt

Vedclass · Accepted Answer

$0.2$

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(B) Elevation in boiling point $(\Delta T_b)$ is a colligative property,which depends on the number of particles in the solution.The formula is $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor.For sucrose (a non-electrolyte),$i = 1$. Thus,$\Delta T_b(	ext{sucrose}) = 1 	imes K_b 	imes m = 0.1\,^{\circ}C$.For $NaCl$ (a strong electrolyte),it dissociates as $NaCl ightarrow Na^+ + Cl^-$,so $i = 2$.Thus,$\Delta T_b(NaCl) = 2 	imes K_b 	imes m = 2 	imes (K_b 	imes m) = 2 	imes 0.1\,^{\circ}C = 0.2\,^{\circ}C$.

If for a sucrose solution the elevation in boiling point is $0.1\,^{\circ}C$,then what will be the elevation in boiling point of a $NaCl$ solution for the same molal concentration? (in $^{\circ}C$)

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