If force F is increasing with time and at t=0 | vedclass

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(B) Let the masses be $m_3 = 3\,kg$,$m_2 = 2\,kg$,and $m_1 = 1\,kg$. The coefficients of friction are $\mu_{32} = 0.5$,$\mu_{21} = 0.3$,and $\mu_{1g}

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between $1\,kg$ and ground

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(B) Let the masses be $m_3 = 3\,kg$,$m_2 = 2\,kg$,and $m_1 = 1\,kg$. The coefficients of friction are $\mu_{32} = 0.5$,$\mu_{21} = 0.3$,and $\mu_{1g} = 0.1$. Assuming $g = 10\,m/s^2$,the maximum static friction forces are: $f_{1,max} = \mu_{32} m_3 g = 0.5 	imes 3 	imes 10 = 15\,N$ $f_{2,max} = \mu_{21} (m_3 + m_2) g = 0.3 	imes (3 + 2) 	imes 10 = 15\,N$ $f_{3,max} = \mu_{1g} (m_3 + m_2 + m_1) g = 0.1 	imes (3 + 2 + 1) 	imes 10 = 6\,N$ As $F$ increases,the entire system moves together until the applied force $F$ exceeds the maximum static friction at any interface. Slipping starts at the interface where the required force to maintain equilibrium is first exceeded by the applied force $F$. Comparing the maximum friction values,$f_{3,max} = 6\,N$ is the smallest. Therefore,the system will first start slipping between the $1\,kg$ block and the ground when $F > 6\,N$.

If force $F$ is increasing with time and at $t=0, F=0$,where will slipping first start?

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