If force overrightarrow F = 4hat i + 5hat j a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Work done $W$ is defined as the dot product of force $\overrightarrow F$ and displacement $\overrightarrow s$.$W = \overrightarrow F \cdot \overri

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) Work done $W$ is defined as the dot product of force $\overrightarrow F$ and displacement $\overrightarrow s$.$W = \overrightarrow F \cdot \overrightarrow s$Given $\overrightarrow F = 4\hat i + 5\hat j$ and $\overrightarrow s = 3\hat i + 6\hat k$.$W = (4\hat i + 5\hat j) \cdot (3\hat i + 6\hat k)$Using the properties of unit vectors $\hat i \cdot \hat i = 1$, $\hat j \cdot \hat j = 1$, $\hat k \cdot \hat k = 1$, and $\hat i \cdot \hat j = \hat j \cdot \hat k = \hat k \cdot \hat i = 0$:$W = (4 	imes 3)(\hat i \cdot \hat i) + (4 	imes 6)(\hat i \cdot \hat k) + (5 	imes 3)(\hat j \cdot \hat i) + (5 	imes 6)(\hat j \cdot \hat k)$$W = 12(1) + 0 + 0 + 0 = 12 	ext{ J}$.

If force $\overrightarrow F = 4\hat i + 5\hat j$ and displacement $\overrightarrow s = 3\hat i + 6\hat k$, then the work done is: (in $\text{ J}$)

Similar Questions

When is the work done by a force positive and when is it negative?

$A$ $50\,kg$ man with a $20\,kg$ load on his head climbs up $20$ steps of $0.25\,m$ height each. The work done in climbing is......$J$

$A$ body of mass $100 \, g$ is rotating in a circular path of radius $r$ with constant velocity. The work done in one complete revolution is

$A$ block of mass $m$,kept on a horizontal surface,is moved through a distance $s$ by applying a horizontal force $F$ to it. What is the work done by the normal reaction?

$A$ man of mass $50 \ kg$ carrying a load of $10 \ kg$ reaches the top of a building in $4 \ minutes$. The work done by the man is $6 \times 10^4 \ J$. If he reaches the top in $2 \ minutes$,the work done by the man will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module