If force vec{F} = 3 hat{i} + 4 hat{j} - 2 hat | vedclass

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Question

(B) The torque $\vec{	au}$ is given by the cross product of the position vector $\vec{r}$ and the force vector $\vec{F}$:$\vec{	au} = \vec{r} 	imes

Vedclass · Accepted Answer

$-10 \hat{i} + 10 \hat{j} + 5 \hat{k}$

Vedclass · Answer

(B) The torque $\vec{	au}$ is given by the cross product of the position vector $\vec{r}$ and the force vector $\vec{F}$:$\vec{	au} = \vec{r} 	imes \vec{F}$Using the determinant form for the cross product:$\vec{	au} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 2 & 1 & 2 \ 3 & 4 & -2 \end{vmatrix}$Expanding the determinant:$\vec{	au} = \hat{i} [(1)(-2) - (2)(4)] - \hat{j} [(2)(-2) - (2)(3)] + \hat{k} [(2)(4) - (1)(3)]$$\vec{	au} = \hat{i} [-2 - 8] - \hat{j} [-4 - 6] + \hat{k} [8 - 3]$$\vec{	au} = -10 \hat{i} + 10 \hat{j} + 5 \hat{k}$

If force $\vec{F} = 3 \hat{i} + 4 \hat{j} - 2 \hat{k}$ acts on a particle having position vector $\vec{r} = 2 \hat{i} + \hat{j} + 2 \hat{k}$,then the torque about the origin will be:

Similar Questions

The vector sum of a system of non-collinear forces acting on a rigid body is given to be nonzero. If the vector sum of all the torques due to the system of forces about a certain point is found to be zero,does this mean that it is necessarily zero about any arbitrary point?

What is the torque of a force $\vec{F} = 3\hat{i} + 7\hat{j} + 4\hat{k}$ about the origin,if the force acts on a particle whose position vector is $\vec{r} = 2\hat{i} + 2\hat{j} + 1\hat{k}$?

The torque of the force $\vec{F} = (2\hat{i} - 3\hat{j} + 4\hat{k}) \text{ N}$ acting at the point $\vec{r} = (3\hat{i} + 2\hat{j} + 3\hat{k}) \text{ m}$ about the origin is:

What is the torque of force $\vec F = 2\hat i - 3\hat j + 4\hat k$ acting at a point $\vec r = 3\hat i + 2\hat j + 3\hat k$ about the origin?

$A$ couple produces:

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