If formaldehyde and potassium hydroxide are heated,then we get

Match List-$I$ with List-$II$.

List-$I$	List-$II$
$1.$ Ammoniacal $AgNO_3$	$a.$ Primary amine
$2.$ $HIO_4$	$b.$ Aldehyde
$3.$ Alkaline $KMnO_4$	$c.$ Vicinal-$OH$
$4.$ Chloroform $NaOH$	$d.$ Double bond

Compounds containing two $-OH$ groups on the same carbon atom are generally unstable,but which of the following is stable?

Which reagent is used to distinguish between acetaldehyde and acetophenone?

The reagent with which both aldehyde and acetone react easily is

$A$ tertiary alcohol $H$ upon acid-catalysed dehydration gives a product $I$. Ozonolysis of $I$ leads to compounds $J$ and $K$. Compound $J$ upon reaction with $KOH$ gives benzyl alcohol and a compound $L$,whereas $K$ on reaction with $KOH$ gives only $M$.
$1.$ Compound $H$ is formed by the reaction of
$2.$ The structure of compound $I$ is
$3.$ The structures of compounds $J, K$ and $L$,respectively,are
$(A)$ $PhCOCH_3, PhCH_2 COCH_3$ and $PhCH_2 COO^{-} K^{+}$
$(B)$ $PhCHO, PhCH_2 CHO$ and $PhCOO^{-} K^{+}$
$(C)$ $PhCOCH_3, PhCH_2 CHO$ and $CH_3 COO^{-} K^{+}$
$(D)$ $PhCHO, PhCOCH_3$ and $PhCOO^{-} K^{+}$
Give the answer for questions $1, 2$ and $3.$