If in $NH_3$ formation $N$ uses its pure atomic orbitals,then the wrong statement is:

  • A
    At least three bond angles are of $90^{\circ}$
  • B
    Three $\sigma$ bonds with identical strength
  • C
    Lone pair will be in $2s$ orbital
  • D
    Molecule will be $T$-shaped

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Similar Questions

Determine the correct $(T)$ and incorrect $(F)$ statements for the permanganate ion $(MnO_4^-)$:
$(a)$ $MnO_4^-$ contains $\sigma$ bonds.
$(b)$ $MnO_4^-$ contains $\pi$ bonds.
$(c)$ $MnO_4^-$ contains both $\sigma$ and $\pi$ bonds.
$(d)$ $MnO_4^-$ is paramagnetic.

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What is the formal charge on the $N$ atom in the $NH_4^{+}$ ion?

Select true or false statements :
$(a)$ Promotion of electron is essential condition prior to hybridisation
$(b)$ In $VSEPR$ theory,two or three electron pairs of a multiple bond are treated as a single super pair
$(c)$ Bond length for $CO_2$ lies between double and triple bonds
$(d)$ $Ne_2$ does not exist

Difficult
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Number of molecules from the following which are exceptions to the octet rule is. . . .
$CO_2, NO_2, H_2SO_4, BF_3, CH_4, SiF_4, ClO_2, PCl_5, BeF_2, C_2H_6, CHCl_3, CBr_4$

Select the correct statement.

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