If in a p-n junction diode,a square input sig | vedclass

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Question

(A) The circuit consists of a $p-n$ junction diode in series with a load resistor $R_L$. When the input voltage is $+5\, V$,the diode is forward-biase

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(A) The circuit consists of a $p-n$ junction diode in series with a load resistor $R_L$. When the input voltage is $+5\, V$,the diode is forward-biased. Assuming an ideal diode,it acts as a short circuit,and the entire input voltage of $+5\, V$ appears across the load resistor $R_L$. When the input voltage is $-5\, V$,the diode is reverse-biased. It acts as an open circuit,and no current flows through the resistor $R_L$. Therefore,the output voltage across $R_L$ is $0\, V$. Thus,the output signal is a square wave that varies between $+5\, V$ and $0\, V$.

If in a $p-n$ junction diode,a square input signal of $10\, V$ (varying from $+5\, V$ to $-5\, V$) is applied as shown,then the output signal across $R_L$ will be:

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