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(D) The given circuit is a half-wave rectifier circuit.When the input signal is positive $(+5\,V)$,the diode is in forward bias and acts as a closed s

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(D) The given circuit is a half-wave rectifier circuit.When the input signal is positive $(+5\,V)$,the diode is in forward bias and acts as a closed switch. Thus,the output voltage across $R_L$ is equal to the input voltage,which is $5\,V$.When the input signal is negative $(-5\,V)$,the diode is in reverse bias and acts as an open switch. Thus,no current flows through $R_L$,and the output voltage across $R_L$ is $0\,V$.Therefore,the output across $R_L$ will be a square wave with a peak voltage of $5\,V$ during the positive half-cycle and $0\,V$ during the negative half-cycle.

If in a $p-n$ junction circuit,a square input signal of $5\,V$ is applied as shown,then the output across $R_L$ will be:

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