If in a compound microscope, the objective has a focal length of $1.0 \text{ cm}$, the eyepiece has a focal length of $2.0 \text{ cm}$, the tube length is $20 \text{ cm}$, and the near point for an observer is $25 \text{ cm}$, then the value of the magnification of the compound microscope will be . . . . . . .
- A$2.5$
- B$250$
- C$25$
- D$2500$
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