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Question

(A) For a moderately asymmetrical (skewed) distribution,the empirical relationship between mean,median,and mode is given by:Mode = $3 	imes 	ext{med

Vedclass · Accepted Answer

$8 \lambda$

Vedclass · Answer

(A) For a moderately asymmetrical (skewed) distribution,the empirical relationship between mean,median,and mode is given by:Mode = $3 	imes 	ext{median} - 2 	imes 	ext{mean}$Given:Mode = $6 \lambda$Mean = $9 \lambda$Substituting these values into the formula:$6 \lambda = 3 	imes 	ext{median} - 2 	imes (9 \lambda)$$6 \lambda = 3 	imes 	ext{median} - 18 \lambda$$3 	imes 	ext{median} = 6 \lambda + 18 \lambda$$3 	imes 	ext{median} = 24 \lambda$Median = $\frac{24 \lambda}{3} = 8 \lambda$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
$f_i$	$2$	$18$	$30$	$45$	$35$	$20$	$6$	$3$

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$
Frequency $(f_i)$	$3$	$4$	$7$	$11$	$2$	$5$

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

If in a moderately asymmetrical distribution,the mode and mean of the data are $6 \lambda$ and $9 \lambda$ respectively,then the median is:

Similar Questions

Find the mode of the given frequency distribution.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

$f_i$ $2$ $18$ $30$ $45$ $35$ $20$ $6$ $3$

The mode of the following frequency distribution is:

Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$ $25-30$

Frequency $(f_i)$ $3$ $4$ $7$ $11$ $2$ $5$

Consider the following frequency distribution:

Class $0-6$ $6-12$ $12-18$ $18-24$ $24-30$

Frequency $a$ $b$ $12$ $9$ $5$

If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$

For a discrete series (where all values are not equal),what is the relationship between Mean Deviation $(M.D.)$,Mean $(Mean)$,and Standard Deviation $(S.D.)$?

In a moderately asymmetrical distribution,the mode and mean are $7$ and $4$ respectively. The median is:

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