If in a nuclear fission,a piece of uranium of | vedclass

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(A) The energy released in a nuclear process is given by Einstein's mass-energy equivalence formula: $E = \Delta m c^2$.Given mass loss $\Delta m = 0.

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$1.25 	imes 10^7$

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(A) The energy released in a nuclear process is given by Einstein's mass-energy equivalence formula: $E = \Delta m c^2$.Given mass loss $\Delta m = 0.5\, g = 0.5 	imes 10^{-3}\, kg$.The speed of light $c = 3 	imes 10^8\, m/s$.Substituting the values: $E = (0.5 	imes 10^{-3}) 	imes (3 	imes 10^8)^2 = 0.5 	imes 10^{-3} 	imes 9 	imes 10^{16} = 4.5 	imes 10^{13}\, J$.To convert energy from Joules $(J)$ to kilowatt-hours $(kWh)$,we divide by $3.6 	imes 10^6\, J/kWh$:$E = \frac{4.5 	imes 10^{13}}{3.6 	imes 10^6} = 1.25 	imes 10^7\, kWh$.

If in a nuclear fission,a piece of uranium of mass $0.5\, g$ is lost,the energy obtained in $kWh$ is

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