If light of wavelength lambda_1 is allowed to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Einstein's photoelectric equation,the energy of an incident photon is equal to the sum of the work function $(W_0)$ and the maximum k

Vedclass · Accepted Answer

$\frac{E_1 \lambda_1 - E_2 \lambda_2}{\lambda_2 - \lambda_1}$

Vedclass · Answer

(C) According to Einstein's photoelectric equation,the energy of an incident photon is equal to the sum of the work function $(W_0)$ and the maximum kinetic energy $(K_{max})$ of the emitted photoelectron.For wavelength $\lambda_1$: $\frac{hc}{\lambda_1} = W_0 + E_1$  --- $(1)$For wavelength $\lambda_2$: $\frac{hc}{\lambda_2} = W_0 + E_2$  --- $(2)$From equation $(1)$,$hc = W_0 \lambda_1 + E_1 \lambda_1$.From equation $(2)$,$hc = W_0 \lambda_2 + E_2 \lambda_2$.Equating the two expressions for $hc$:$W_0 \lambda_1 + E_1 \lambda_1 = W_0 \lambda_2 + E_2 \lambda_2$Rearranging to solve for $W_0$:$W_0 \lambda_1 - W_0 \lambda_2 = E_2 \lambda_2 - E_1 \lambda_1$$W_0 (\lambda_1 - \lambda_2) = E_2 \lambda_2 - E_1 \lambda_1$$W_0 = \frac{E_2 \lambda_2 - E_1 \lambda_1}{\lambda_1 - \lambda_2} = \frac{E_1 \lambda_1 - E_2 \lambda_2}{\lambda_2 - \lambda_1}$

If light of wavelength $\lambda_1$ is allowed to fall on a metal,then the kinetic energy of the photoelectrons emitted is $E_1$. If the wavelength of light changes to $\lambda_2$,then the kinetic energy of the electrons changes to $E_2$. Then the work function of the metal is:

Similar Questions

$A$ particle of mass $200\,g$ executes a simple harmonic motion. The restoring force is provided by a spring of spring constant $80\,N/m$. The time period is .... $sec$.

$A$ disc of radius $R$ and thickness $\frac{R}{6}$ has a moment of inertia $I$ about an axis passing through its centre and perpendicular to its plane. The disc is melted and recast into a solid sphere. The moment of inertia of the sphere about its diameter is

The ionization energy of $He^+$ is $19.6 \times 10^{-18} \ J \ atom^{-1}$. What is the energy of the first stationary state $(n = 1)$ of $Li^{2+}$?

The area (in square units) of the triangle formed by the points with polar coordinates $(1, 0)$,$(2, \frac{\pi}{3})$,and $(3, \frac{2\pi}{3})$ is

$A$ variable plane is at a constant distance $h$ from the origin and meets the coordinate axes in $A, B, C$. The locus of the centroid of $\triangle ABC$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module