If the mass of a He atom is 4 times that of a | vedclass

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(B) The mean velocity of gas molecules is given by the formula $v_{av} = \sqrt{\frac{8RT}{\pi M}}$.From this expression,we can see that the mean veloc

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$1/2$ times the $H$-mean value

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(B) The mean velocity of gas molecules is given by the formula $v_{av} = \sqrt{\frac{8RT}{\pi M}}$.From this expression,we can see that the mean velocity is inversely proportional to the square root of the molar mass: $v_{av} \propto \frac{1}{\sqrt{M}}$.Given that the mass of a $He$ atom $(M_{He})$ is $4$ times the mass of a hydrogen atom $(M_H)$,we have $M_{He} = 4M_H$.Taking the ratio of the mean velocities:$\frac{v_{He}}{v_H} = \sqrt{\frac{M_H}{M_{He}}} = \sqrt{\frac{M_H}{4M_H}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Therefore,$v_{He} = \frac{1}{2} v_H$.

If the mass of a $He$ atom is $4$ times that of a hydrogen atom,then the mean velocity of $He$ is:

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