If matrix A = begin{bmatrix} 0 & -1 1 & 0 en | vedclass

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(D) Given,matrix $A = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix}$.First,we calculate $A^2$:$A^2 = A \cdot A = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{

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$\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$

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(D) Given,matrix $A = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix}$.First,we calculate $A^2$:$A^2 = A \cdot A = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} = \begin{bmatrix} (0)(0) + (-1)(1) & (0)(-1) + (-1)(0) \ (1)(0) + (0)(1) & (1)(-1) + (0)(0) \end{bmatrix} = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix} = -I$,where $I$ is the identity matrix.Now,we calculate $A^{16}$:$A^{16} = (A^2)^8 = (-I)^8 = (-1)^8 \cdot I^8 = 1 \cdot I = I$.Thus,$A^{16} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$.

If matrix $A = \begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix}$,then $A^{16} = $

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