If momentum is increased by 20 %, then kineti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relationship between kinetic energy $K$ and momentum $P$ is given by $K = \frac{P^2}{2m}$.Let the initial momentum be $P$ and the initial kine

Vedclass · Accepted Answer

$44$

Vedclass · Answer

(B) The relationship between kinetic energy $K$ and momentum $P$ is given by $K = \frac{P^2}{2m}$.Let the initial momentum be $P$ and the initial kinetic energy be $K = \frac{P^2}{2m}$.If the momentum is increased by $20 \%$, the new momentum $P'$ becomes $P' = P + 0.20P = 1.2P$.The new kinetic energy $K'$ is given by $K' = \frac{(P')^2}{2m} = \frac{(1.2P)^2}{2m} = \frac{1.44P^2}{2m}$.Substituting $K = \frac{P^2}{2m}$, we get $K' = 1.44K$.The percentage increase in kinetic energy is given by $\frac{K' - K}{K} 	imes 100 \% = \frac{1.44K - K}{K} 	imes 100 \% = 0.44 	imes 100 \% = 44 \%$.

If momentum is increased by $20 \%$, then kinetic energy increases by (in $\%$)

Similar Questions

An object of $1 \, kg$ mass has a momentum of $10 \, kg \cdot m/s$. Then,the kinetic energy of the object will be .............. $J$.

$A$ body of mass $2 \ kg$ is projected vertically upwards with a velocity of $2 \ m \ s^{-1}$. What will be its kinetic energy in $J$ just before it hits the ground?

$A$ man increases his speed by $2 \ m/s$, and as a result, his kinetic energy doubles. What was his initial speed?

Two bodies of masses $m$ and $4m$ are moving with equal kinetic energy $(K.E.)$. The ratio of their linear momentums is

Which of the following graphs represents the graphical relation between momentum $(p)$ and kinetic energy $(K)$ for a body in motion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module