(C) According to Faraday's law of electrolysis,the mass $m$ deposited is given by $m = \frac{E \times I \times t}{F}$,where $E$ is the equivalent weig

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) According to Faraday's law of electrolysis,the mass $m$ deposited is given by $m = \frac{E \times I \times t}{F}$,where $E$ is the equivalent weight,$I$ is current in amperes,$t$ is time in seconds,and $F$ is the charge required for $1 \ gm$ equivalent (given as $10^5 \ C$).Given: $E = 9$,$I = 50 \ A$,$t = 20 \ minutes = 20 \times 60 \ s = 1200 \ s$,and $F = 10^5 \ C$.Substituting the values: $m = \frac{9 \times 50 \times 1200}{10^5} = \frac{540000}{100000} = 5.4 \ gm$.

Class 12 Chemistry Electrochemistry Faraday’s law of electrolysis

Medium

If nearly $10^5 \ C$ liberate $1 \ gm$ equivalent of aluminium,then the amount of aluminium (equivalent weight $9$) deposited through electrolysis in $20 \ minutes$ by a current of $50 \ A$ will be .............. $gm$.

AIPMT 1998 All AIPMT

A
$0.6$
B
$0.09$
C
$5.4$
D
$10.8$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Electrochemistry

Subtopic

Faraday’s law of electrolysis

Previous Year

AIPMT 1998 Paper All AIPMT years →

The mass of a substance liberated when a charge $q$ flows through an electrolyte is proportional to

Easy

View Solution

Electrolysis of $600 \ mL$ aqueous solution of $NaCl$ for $5 \ min$ changes the $pH$ of the solution to $12$. The current in Amperes used for the given electrolysis is $...........$. $(Nearest \ integer)$.

DifficultJEE MAIN 2025

View Solution

$A$ solution of a salt of a metal was electrolysed for $150$ minutes with a current of $0.15$ amperes. The weight of metal deposited was $0.783 \ g$. The equivalent weight of the metal is ................... $g$. (in $.97$)

Medium

View Solution

The mass of carbon anode consumed (giving only carbon dioxide) in the production of $270 \ kg$ of aluminium metal from bauxite by the Hall process is ............... $kg$.

MediumAIPMT 2005

View Solution

The density and equivalent weight of a metal are $10.5\, g\, cm^{-3}$ and $100$,respectively. The time required for a current of $3\, A$ to deposit a $0.005\, mm$ thick layer of the same metal on an area of $80\, cm^2$ is closest to $....\, s$

DifficultKVPY 2013

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

If nearly $10^5 \ C$ liberate $1 \ gm$ equivalent of aluminium,then the amount of aluminium (equivalent weight $9$) deposited through electrolysis in $20 \ minutes$ by a current of $50 \ A$ will be .............. $gm$.

Similar Questions

The mass of a substance liberated when a charge $q$ flows through an electrolyte is proportional to

Electrolysis of $600 \ mL$ aqueous solution of $NaCl$ for $5 \ min$ changes the $pH$ of the solution to $12$. The current in Amperes used for the given electrolysis is $...........$. $(Nearest \ integer)$.

$A$ solution of a salt of a metal was electrolysed for $150$ minutes with a current of $0.15$ amperes. The weight of metal deposited was $0.783 \ g$. The equivalent weight of the metal is ................... $g$. (in $.97$)

The mass of carbon anode consumed (giving only carbon dioxide) in the production of $270 \ kg$ of aluminium metal from bauxite by the Hall process is ............... $kg$.

The density and equivalent weight of a metal are $10.5\, g\, cm^{-3}$ and $100$,respectively. The time required for a current of $3\, A$ to deposit a $0.005\, mm$ thick layer of the same metal on an area of $80\, cm^2$ is closest to $....\, s$

Vedclass Test Series

Exam Paper Generator

Online Exam Module