If one factor of $x^{3}+4 x^{2}+8 x+a$ is $(x+2)$,then find the value of $a$.

Draw the graph of $p(x) = x^3 - 2x^2$ and find the zeros of this polynomial.

For the given sum and product of zeroes,find the quadratic polynomial. Also,find the zeroes of this polynomial by factorization:
Sum of zeroes = $-2 \sqrt{3}$,Product of zeroes = $-9$.

Divide $x^{4}+4 x^{3}-2 x^{2}-12 x+9$ by $x^{2}-2 x+1$.

The degree of the polynomial $p(x) = 3x - x^4 + x^2 + 2x^3 + 7$ is ..........

The graph of $p(x) = x^{2} + 6x + 9$ intersects the $X$-axis $\ldots \ldots \ldots \ldots$