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(A) Let the coordinates of the other end point of the diameter be $(x,y).$Since the centre of a circle is the midpoint of its diameter,we use the midp

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$(-4,8)$

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(A) Let the coordinates of the other end point of the diameter be $(x,y).$Since the centre of a circle is the midpoint of its diameter,we use the midpoint formula:Centre $= (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$Given the centre is $(-2,4)$ and one end point is $(0,0)$,we have:$-2 = \frac{0 + x}{2} \implies x = -4$$4 = \frac{0 + y}{2} \implies y = 8$Therefore,the other end point is $(-4,8).$

If one of the end points of the diameter of a circle is $(0,0)$ and the centre of the circle is $(-2,4),$ then the other end point of the diameter is.........

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