(B) Let the first root be $\alpha$. Since the second root is the reciprocal of the first,the second root is $\frac{1}{\alpha}$. For a quadratic equati

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(B) Let the first root be $\alpha$. Since the second root is the reciprocal of the first,the second root is $\frac{1}{\alpha}$. For a quadratic equation $ax^2 + bx + c = 0$,the product of the roots is given by $\frac{c}{a}$. Here,$a = 5$,$b = 13$,and $c = k$. Therefore,the product of the roots is $\alpha \times \frac{1}{\alpha} = \frac{k}{5}$. $1 = \frac{k}{5}$. $k = 5$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Relation between roots and coefficients

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If one root of $5x^2 + 13x + k = 0$ is the reciprocal of the other,then $k = $?

A
$0$
B
$5$
C
$1/6$
D
$6$

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4-2.Quadratic Equations and Inequations

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Relation between roots and coefficients

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If one root of $5x^2 + 13x + k = 0$ is the reciprocal of the other,then $k = $?

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