If the period number and group number of any | vedclass

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Question

(C) The representative elements where the period number equals the group number are $H$ ($1s^1$,Period $1$,Group $1$) and $Be$ ($1s^2 2s^2$,Period $2$

Vedclass · Accepted Answer

The possible value of magnetic quantum number is $1$

Vedclass · Answer

(C) The representative elements where the period number equals the group number are $H$ ($1s^1$,Period $1$,Group $1$) and $Be$ ($1s^2 2s^2$,Period $2$,Group $2$).For $H$ $(1s^1)$: Principal quantum number $n = 1$,Azimuthal quantum number $l = 0$,Magnetic quantum number $m_l = 0$. It is paramagnetic.For $Be$ $(1s^2 2s^2)$: Principal quantum number $n = 2$,Azimuthal quantum number $l = 0$,Magnetic quantum number $m_l = 0$. It is diamagnetic.In both cases,the magnetic quantum number $m_l$ is $0$,not $1$. Therefore,statement $(c)$ is incorrect.

If the period number and group number of any representative element are the same,then which of the following statements is incorrect regarding such type of element in its ground state? (Period number and group number are according to the modern form of the periodic table)

Similar Questions

The electronic configurations of $4$ atoms are given below:
$P = [Ne] \, 3s^2 3p^3$
$Q = [Ar] \, 3d^{10} 4s^2 4p^3$
$R = [He] \, 2s^2 2p^5$
$S = [Ne] \, 3s^1$
Which of the following statements is incorrect?

Choose the correct statement.

In which of the following sets,elements are not correctly arranged with the property shown in brackets?

The statement that is true for the long form of the periodic table is

Which has maximum $EA$,$EN$ and $IP$ respectively $:-$
$A = 1s^2 \ 2s^2 \ 2p^6$
$B = 1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^5$
$C = 1s^2 \ 2s^2 \ 2p^5$
$D = 1s^2 \ 2s^2 \ 2p^6 \ 3s^1$

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