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(B) The work done in changing the potential difference across a capacitor is given by the change in stored energy: $\Delta U = \frac{1}{2} C(V_f^2 - V

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(B) The work done in changing the potential difference across a capacitor is given by the change in stored energy: $\Delta U = \frac{1}{2} C(V_f^2 - V_i^2).$In the first case,the potential changes from $15 \ V$ to $30 \ V$:$W = \frac{1}{2} C(30^2 - 15^2) = \frac{1}{2} C(900 - 225) = \frac{1}{2} C(675) = 337.5 C.$So,$C = \frac{W}{337.5}.$In the second case,the potential changes from $30 \ V$ to $60 \ V$:$W' = \frac{1}{2} C(60^2 - 30^2) = \frac{1}{2} C(3600 - 900) = \frac{1}{2} C(2700) = 1350 C.$Substituting $C = \frac{W}{337.5}$ into the equation for $W'$:$W' = 1350 	imes \left( \frac{W}{337.5} ight) = 4W.$

If potential difference across a capacitor is changed from $15 \ V$ to $30 \ V,$ work done is $W.$ The work done,when potential difference is changed from $30 \ V$ to $60 \ V,$ will be $.......W$

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