If the roots of x^2 - 7x + 6 = 0 are alpha an | vedclass

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(B) For the quadratic equation $ax^2 + bx + c = 0$,the sum of roots $\alpha + \beta = -b/a$ and the product of roots $\alpha \beta = c/a$.Given equati

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$7/6$

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(B) For the quadratic equation $ax^2 + bx + c = 0$,the sum of roots $\alpha + \beta = -b/a$ and the product of roots $\alpha \beta = c/a$.Given equation: $x^2 - 7x + 6 = 0$.Here,$a = 1, b = -7, c = 6$.Sum of roots $\alpha + \beta = -(-7)/1 = 7$.Product of roots $\alpha \beta = 6/1 = 6$.We need to find $\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}$.Substituting the values,we get $\frac{7}{6}$.

If the roots of $x^2 - 7x + 6 = 0$ are $\alpha$ and $\beta$,then find the value of $\frac{1}{\alpha} + \frac{1}{\beta}$.

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