If the solubility of $NaCl$ at $20\,^{\circ}C$ is $35\,g$ per $100\,g$ of water,then on adding $50\,g$ of $NaCl$ to the same amount of water at the same temperature,the amount of salt that remains undissolved is .......... $g$.

  • A
    $15$
  • B
    $20$
  • C
    $50$
  • D
    $35$

Explore More

Similar Questions

The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportions of $20 \%$ and $79 \%$ by volume at $298 \ K$. The water is in equilibrium with air at a total pressure of $10 \ atm$. At $298 \ K$,if the Henry's law constants for oxygen and nitrogen are $3.30 \times 10^{7} \ mm \ Hg$ and $6.51 \times 10^{7} \ mm \ Hg$ respectively,calculate the mole fractions of these gases in water.

Difficult
View Solution

The oxygen dissolved in water exerts a partial pressure of $20 \ kPa$ in the vapour above water. The molar solubility of oxygen in water is ............ $\times 10^{-5} \ mol \ dm^{-3}$ (Round off to the Nearest Integer). [Given: Henry's law constant $K_H = 8.0 \times 10^{4} \ kPa$ for $O_2$,Density of water $= 1.0 \ kg \ dm^{-3}$]

Which among the following salts shows a decrease in solubility with an increase in temperature?

Calculate the solubility of a gas in a solvent at $25^{\circ} C$ and $0.8 \ atm$ if Henry's law constant for the solvent is $6.8 \times 10^{-4} \ mol \ dm^{-3} \ atm^{-1}$.

The partial pressure of ethane over a solution containing $7.14 \times 10^{-3} \ g$ of ethane is $1 \ bar$. If the solution contains $5 \times 10^{-2} \ g$ of ethane,then what shall be the partial pressure of the gas (in $bar$)? (At equal temperature)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo